70x^2+128x+42=0

Solution for 70x^2+128x+42=0 equation:

70x^2+128x+42=0

a = 70; b = 128; c = +42;
Δ = b2-4ac
Δ = 1282-4·70·42
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-68}{2*70}=\frac{-196}{140}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+68}{2*70}=\frac{-60}{140}
=-3/7
$